Given an array of length n initially filled with zeros, process two types of operations: assign every value in a range to a constant, and query the sum of a range. Return all query answers in order. This is a classic lazy propagation problem because range assignment must be pushed down efficiently.
n = array length, operations = range assignments and sum queries
sum for every type-2 query, in order
Example 1:
Input:
n = 5 operations = [[1,1,3,2],[2,0,4],[1,2,4,1],[2,0,4]]
Output:
[6,5]
Explanation:
After assigning 2 to indices 1 through 3, the sum is 6. After reassigning 1 to indices 2 through 4, the total becomes 5.
Example 2:
Input:
n = 4 operations = [[1,0,2,3],[2,1,3],[1,1,1,0],[2,0,3]]
Output:
[6,6]
Explanation:
The first query sees [3,3,3,0] on indices 1..3. After the second assignment, the array becomes [3,0,3,0], whose total sum is 6.